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Segmented Basket Illusion Vase Demonstration
with Bob Grinstead
Segmented Basket Illusion Vase Demonstration with Bob Grinstead
Bob Grinstead demonstrated his techniques for making a basket illusion segmented vase, and a basket illusion carved vase during our meeting March 19th. Video of that meeting and the separate videos of the demonstrations can be found on our YouTube channel, @worldwidewoodturners1.
This is my try at Ross McClelland’s woven vase. He posted it on the Segmented Bowl Turning Face Book group. It is not a conventional segmented build but it is easier than it looks. Just take your time placing the verticals and then cutting the horizontal pieces by hand.
Let me take you through the build of this vase.
Draw out the vase you want on graph paper. I lay my vases and bowls out on 1/4″ graph paper I make using Excel but you can just buy the paper. Every 4 squares make 1″. Draw in the shape of the vase then draw in the wall thickness.
Color in the squares it will take to make your material fit the walls you drew. . Most of the time my material is 3/4″ thick. If it is thicker or thinner, don’t worry about it, it doesn’t matter much. So a colored cube, 3 squares vertical and 4 square wide equals a 3/4″ H x 1″ W block. Make sure your blocks are wide enough to accommodate the curve of the vessel. Error on the wide side. Glued up rings are seldom truly round, so when you glue them on top of each other they might shift a little one way or the other.
This vase consist of 10 verticals and 10 horizonal pieces for each ring. Cut all of the verticals first out of 3/4″ material. Most will be 1-1/4″ tall and the width depends on the width you need for each ring. Some rings will be different widths to accommodate the walls of the vessel.
The first and last ring will also have 10 verticals each that are only 1/4″ tall
I use the standard formulas for segmented rings to figure out the top edge of each segment in each ring. When you lay it out on graph paper you are working with only half of the vessel or the radius of each ring.
Closed Ring Segment Formulas: ((R*2*3.14)/S)*1.024 R – radius S – number of segments per ring 1.024 - fudge factor

(Rings with a small number of segments (like 12) need a fudge factor to keep the final ring size true.
Rings with 18 or more segments per ring probably don’t need this.)
Example= 4” radius of ring, 10 segments per ring ((4″ x 2 x 3.14) /10) x 1.024 = 2.572”
The angles on each end of a segment in a closed ring is (360/# of S)/2.
Example: The last ring is a true closed segment ring of 20 segments.
The angles on each end of the segments will be (360/20) /2 = 9 degrees.
I use this information to determine how much material I need for each ring. Just multiple each segment length by the number of segments for that ring plus a few inches for the saw kerf and waste material.
Since both the verticals and horizontals are out of 3/4″ stock just ensure you have enough material of the same width to make both the verticals and horizonal pieces for each ring.
It is best to try and keep the grain going in the same direction on each piece of material. If the pieces are small sometimes it is hard to see or keep track of the grain, side vs top.
In our case the horizonal segment length is determined using the formula, minus the thickness of each vertical.
Or in the example above of 10 segments per ring, 2.572 – .75 = 1.822″
So you would need at least 18.22″ (1.822 x 10 segments) of material plus the kerf for each cut (10) and the waste at the end of the stick for just one ring (because you need something to hold on to making the final cut).
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